1. The problem statement, all variables and given/known data "A student whose weight is 500 Newtons stands on a scale in an elevator and records the scale reading as a function of time. The data is shown in the graph above. At time t=0, the elevator is at displacement x=0 with velocity v=0. Assume that the positive directions for displacement, velocity, and acceleration are upward. Graph (scale reading 'newtons' vs time): 0-5 seconds --> 500 Newtons 5-10 seconds --> 700 Newtons 10-15 seconds --> 500 Newtons 15-20 seconds --> 300 Newtons" 3. The attempt at a solution a) Free Body Diagram w/ all forces on the student at t=8 Normal Force going up mg going down b) Calculate the acceleration of the elevator for each 5 second interval 0-5s= 0 m/s^2 because force stays the same meaning its at rest since velocity is 0 at 0seconds 5-10s= fnet=ma 700-500=51a a= 3.92m/s^2 10-15s= force is back to 500 meaning constant velocity a= 0m/s^2 15-20s= fnet=ma 300-500=51a a= -3.92 m/s^2 c) It asks for velocity when t= 5,10,15,20 v=at v=0(5) v= 0 m/s v=vi+at v=0+3.92(5) v= 19.6 m/s v=vi+at v=19.6+0(5) v=19.6 m/s v=19.6+(-3.92)(5) v=0 m/s Now I have to plot this on a velocity vs time graph so I have it at: 0 velocity from 0-5s line from (5,0) to (10,19.6). horizontal line from (10,19.6) to (15,19.6) line from (15,19.6) to (20,0) Just want to see if I am doing this right... Thank you.