# Newtons Law

1. Feb 17, 2009

### papa_smurf493

1. The problem statement, all variables and given/known data

An object with a mass of 4.0 kg travels with a constant velocity of 4.8 m/s northward. It is then acted on by a force of 6.5 N in the direction of motion and a force of 9.5 N to the south, both of which continue even after the mass comes momentarily to rest.

(a) How far will the object travel before coming to rest?

(b) What will be its position 2.5 s after the object comes momentarily to rest?

2. Relevant equations

3. The attempt at a solution
I have 4.0 Kg traveling in one direction and a 3.0 N force (9.5N-6.5N=3.0N) being applied in the other direction. Soon the car will come to a stop and start to accelerate in the forward direction. Plug in the initial conditions of 4.0Kg traveling North at 4.8 m/s being acted upon by a constant 3.0N (Kg/ms^2) south force. (North is usually up and is positive; so a Southern acting force is negative).

I like to reword the question so its relevant to me, but we just started this stuff and i need some help with the equations that i will need to use.

2. Feb 17, 2009

### papa_smurf493

please i have no idea where to start and what equation to use!

3. Feb 17, 2009

### papa_smurf493

ok i tried using x=VoXT + 1/2axt^2 but i dont think it applies because there is no time involved in part a