(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Three blocks are in contact with each other on a frictionless horizontal surface as shown. The masses of the blocks are m1 = 1.0 kg, m2 = 2.0 kg, and m3 = 3.0 kg. A horizontal force F = 24 N is applied to m1.

a. Find the acceleration of the three blocks.

b. Find the net force on each block.

c. Find the magnitudes of the contact forces between the blocks.

2. Relevant equations

Not sure.. [tex]\Sigma[/tex]F = F1+F2+F3

3. The attempt at a solution

a)

F = a (1.0kg + 2.0 kg + 3.0 kg)

24N = a (6 kg)

24N / 6 kg = a

4 m/s^{2}= a

b)

F1 = 1kg (4 m/s2) = 4N

F2 = 2kg (4 m/s2) = 8N

F3 = 3kg (4 m/s2) = 12N

c)

F - F1 = 24N - 4N = 20N (contact force between F1 & F2)

F - F1 - F2 = 24N - 4N - 8N = 12N (contact force between F2 & F3)

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wow I feel lost after what I did.. Does this make sense?

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# Newton's laws 2

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