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Newtons laws friction

  1. Sep 23, 2008 #1
    1. The problem statement, all variables and given/known data

    A 2.8 kg wood block is launched up a wooden ramp that is inclined at a 34° angle. The block’s initial speed is 8.56 m/s. What vertical height does the block reach above its starting point?

    What speed does it have when it slides back down to its starting point?

    2. Relevant equations


    3. The attempt at a solution

    and yea i really dont kno wat to do with this
  2. jcsd
  3. Sep 23, 2008 #2


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    Homework Helper

    Did you draw a free body diagram? You are missing some things. Also, there is an angle involved, so you must resolve your forces into their components.
  4. Sep 24, 2008 #3
    ok so i think i drew it right and this is the equation i got from it
    fnetx= -Fk-Wsin+v=Ma

    how does that give me height and accerelation
  5. Sep 24, 2008 #4
    ok so this is wat i got ignore the last post
    wx=M*gsin = 8.324N
    Fk= Mk*N = 3.9396 N
    Fk-Wx/m= - 4.385 m/s^2
    Xf=xi+(Vf^2-Vi^2/2a)= 9.133
    Xf*sin= 3.8599
    would this be my height????
  6. Sep 24, 2008 #5


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    These are sort of correct, there's a few problems though:

    v is not a force, so you can't add it as one in your equation.

    If you look in the y direction, there is no movement in it; the block stays on the incline. So the acceleration is zero in that direction. This makes your equation simpler.

    Well it will let you solve for acceleration, after which you can work on finding the height.
  7. Sep 24, 2008 #6


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    I'm having trouble understanding what you've done here. I don't see how you got 8.324 N. What did you use for N when you found Fk?
    This doesn't make sense the way you've typed it.

    Take a look at this website, maybe it will help you http://hyperphysics.phy-astr.gsu.edu/hbase/newt.html#nt2cn
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