1. The problem statement, all variables and given/known data A 4.1-kg box is pushed along a horizontal floor by a force of magnitude 21 N at an angle θ = 35° with the horizontal. If the coefficient of kinetic friction between the block and the floor is 0.20, calculate the acceleration of the box. Be careful when calculating the normal force. 2. Relevant equations [tex]\Sigma[/tex]F = ma Ffr= [tex]\mu[/tex]k Fn Fn=mg 3. The attempt at a solution Fcos35°- Ffr = ma 21Ncos35° - [tex]\mu[/tex]k mg = ma 21Ncos35° - 0.20 (4.1 kg) (9.8 m/s2) = (4.1 kg) a (17.2021N - 8.036N) / 4.1 kg = a 2.235 m/s2 = a Is this correct or on the right track?