(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

2 objects with mass m1=10 and m2=5 are connected by a light string that passes over a frictionless pulley, they are set up so that m1 is sitting on the desk and m2 is attached to a pulley, is over he desk. if when the system starts from rest, m2 falls 1 meter in 1.2seconds, determine the coeeficiant of kinectic friction between m1 and the desk.

force Friction = Force normal * cooeficiant of kinetic friction

change in x= v-initial*time + .5(accelration)(time^2)

ok so i first found out what the acceleration would be of m2 under those conidtions, found out the force of it then, and then i found the force for if the accelration of m2 was just 9.8m/s^2, and found the difference between that and the first force, and then set that difference equal to Force normal * cooeficiant of kinetic friction, but i still get the wrong answer for kinetic friction cooeficiant.

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Newtons Laws of Motion!

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