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Joe was driving on the highway a car ahead of him was driving far below the speed limit so he decided to pass. In the first second he gained(gained means to get nearer to something you are chasing) 5m on the car and as he accelerated he gained 1.5 times as much distance in each second as he had the second before. If there was 30 m between joe and the car he was passing then how long did it take him to pass
Correct answer
537/100s
t = 1s
u = s/t=5/1 m/s
a = 1.5 m/s^2
V^2= u^2 +2as
V^2= 5^2+ (2*1.5*2.5)
v = sqrt100=10
v = u + at
10 = 5+ (1.5*t)
105=1.5t
t =5/1.5=3.333
t = 3.33+1=4.33 (one second put because of first gained)
Correct answer
537/100s
t = 1s
u = s/t=5/1 m/s
a = 1.5 m/s^2
V^2= u^2 +2as
V^2= 5^2+ (2*1.5*2.5)
v = sqrt100=10
v = u + at
10 = 5+ (1.5*t)
105=1.5t
t =5/1.5=3.333
t = 3.33+1=4.33 (one second put because of first gained)
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