# Newtons laws problem

Joe was driving on the highway a car ahead of him was driving far below the speed limit so he decided to pass. In the first second he gained(gained means to get nearer to something you are chasing) 5m on the car and as he accelerated he gained 1.5 times as much distance in each second as he had the second before. If there was 30 m between joe and the car he was passing then how long did it take him to pass

537/100s

t = 1s
u = s/t=5/1 m/s
a = 1.5 m/s^2

V^2= u^2 +2as

V^2= 5^2+ (2*1.5*2.5)
v = sqrt100=10

v = u + at
10 = 5+ (1.5*t)
10-5=1.5t
t =5/1.5=3.333
t = 3.33+1=4.33 (one second put because of first gained)

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tiny-tim
Homework Helper
Welcome to PF!

Joe was driving on the highway a car ahead of him was driving far below the speed limit so he decided to pass. In the first second he gained(gained means to get nearer to something you are chasing) 5m on the car and as he accelerated he gained 1.5 times as much distance in each second as he had the second before. If there was 30 m between joe and the car he was passing then how long did it take him to pass

537/100s
Hi brendanmeneze! Welcome to PF! I don't think this has anything to do with Newton or with constant acceleration.

In the first second, he gains 5
In the second second, he gains 5*1.5
In the third second, he gains 5*1.5^2
In the fourth second, he gains 5*1.5^3.

Can you see a pattern? Anyway, after 4 seconds, he gains 5(1 + 1.5 + 2.25 + 3.375) = over 40 metres.

Have I understood the question right? newtons laws motion

you could right there tinytim butt the answers 5.37 s for 30m you got less seconds 4 for more meters 40m unless the answer given 537/100 is wrong. thank you and i believe you are right because laws of motion dont give right answer.

tiny-tim
Yes, I think the answer given is wrong. Finish it anyway … can you see the pattern, and get an equation for the distance as a function of time? 