- #1

- 3

- 0

## Homework Statement

The 100 kg blcok in the figure takes 5.40 s to reach the floor after being released from rest. What is the mass of the block on the left?

## Homework Equations

F=ma

s

_{f}=s

_{i}+ (1/2)(a)(delta t)

## The Attempt at a Solution

I know to find acceleration you use

s

_{f}=s

_{i}+ (1/2)(a)(delta t)

0=1+(1/2)(a)(5.4)

a = 0.0686 m/s

^{2}

and then the F=ma to find the force on the block of known mass.

F=(100 kg)(0.0686)

F=6.86

but from this I am not sure how to determine the mass of the block on the left?