Two toboggans are connected by a rope. The first toboggan has a mas of 60 kg and the second has a mass of 40 kg. The two toboggans are pulled by a rope connected to the first toboggan. If the force exerted on the rope is 250N [E], and friction between the toboggans and the ice and be ignored, find:(adsbygoogle = window.adsbygoogle || []).push({});

(a) the acceleration of the toboggans.

(b) the tension in the rope connecting the toboggans

I found the acceleration to be 2.5m/s^2 and the tension in the rope to be 100N

Question 2 it asks, suppose a third toboggan of mas 25kg is connected tot he second toboggan in question 1. Find:

(a) the acceleration of the system of three toboggans.

(b) the force exerted by toggan one on toboggan two.

(c) the force exerted by the second toboggan on the last one.

I got 2m/s^2 for (a), 130N[E] for b and 50N[E] for c

But what I don't get is when it asks me to repeat question 2 with the coefficient of kinetic friction being 0.10.

I only found the acceleration being 1.02m/s^2. How can I find (b) and (c)?

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# Homework Help: Newton's Laws Quick question

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