In figure 6-36, two blocks are connected over a pulley. The mass of block A is mA and the coeffcient of kinetic friction between A and the incline is Uk. Angle of the incline is theta. Block A slides down the incline at constant speed. What is the mass of block B? Express your answer in terms of the variables given.
F = ma
The Attempt at a Solution
Taking acceleration to be 0, because speed is constant. And that T1 = T2, i came to the answer of
[m1gsin(theta) - m1gcos(theta)Uk] / g = mass of the 2nd block
Can I get a verification
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