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Newton's Laws

1. Homework Statement

A 100 kg block is pulled at a constant speed of 3 m/s across a horizontal floor by an applied foce of 145 N directed 37 degrees above the horizontal. What is the rate at which the force does work on the block? _____ W

2. Homework Equations
work = force (dot product) displacement
work = .5m * v^2 (final) - .5m *v^2 (initial)


3. The Attempt at a Solution

i used the second equation and plugged in my mass as 100kg and my final velocity as 3. so i got .5(100)(3^2) = 450 W. That seems like an awful lot to me ????
 
133
0
Its the rate at which force does work.
What is the rate at which work is done known as?
 
Is it power?
 
This is something else I've tried.

Power = work / time = force (dot product) displacement = force * average velocity * cos(37 desgrees). I cam out with 347. 41 W. Am I doing this correctly?
 
Solved. Thanks for jogging my memory!!
 

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