1. The problem statement, all variables and given/known data A locomotive accelerates a 24-car train along a level track. Every car has a mass of 50000 kg and is subject to a frictional force f = 250 v, where the speed v is in meters per second and the force f is in Newtons. At the instant when the speed of the train is 28 km/h, the magnitude of its acceleration is 0.3 m/s^2. (a) What is the tension in the coupling between the first car and the locomotive? (b) If this tension is equal to the maximum force the locomotive can exert on the train, what is the steepest grade up which the locomotive can pull the train at 28 km/h? 3. The attempt at a solution F-25(250v) = 25(50000)a v=7.778 F = 24(50000)(0.3) + 24(250*7.778) F= 360000 + 46,668 F = 406.7 kN T = 406.7N x 10^3 T= mg*cos(theta) 406.7x10^3/24(50000)(9.81) = cos(theta) theta = 1.98 am i correct?? second part was a mystery, i just tried so many things till the answer seemed right.