Newton's Principia Problem

Furthermore, is there any way of understanding the Principia in a more numerical ways rather than words like this? Just asking.
Again, thank you very much.

Doug Huffman
Gold Member
S. Chandrasekhar Newton's Principia for the Common Reader Chapter 3, Section 15, pp 50-52 in modern integral notation.

Philip Wood
Gold Member
I think that in modern terms, this is $s = \frac{1}{2} a t^2$. So $\frac{s_1}{s_2} = (\frac{t_1}{t_2})^2$. This is constant acceleration from rest. Since it's at the very beginning off the motion, the force won't have had time to change?

Last edited:
Stephen Tashi