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## Homework Statement

Two masses, m1 = 3.50kg and m2 = 5.00 kg, are on a frictionless tabletop and mass m3 = 7.60kg is hanging from m1. THE COEFFICIENT OF STATIC AND KINETIC FRICTION BETWEEN m1 AND m2 are 0.60 and 0.50 respectively.

a) What are the acceleration of m1 and m2?

## Homework Equations

Equation for kinetic and static friction and newton's second law.

## The Attempt at a Solution

I found the acceleration for m1 to be 5.2 m/s^2 by doing

a = ((m3)g - Fk) / (m1 + m3)

Now, I don't know what to do in order to find the acceleration of m2.

Do I have to consider the kinetic friction between m2 and m1 and Newton's third law meaning that m1 exerts a force equal to Fk (force due to kinetic friction) on m2?

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