A cyclist and her bicycle have mass 75kg. she is riding on a horizontal road, and positions herself so that 60% of the normal contact force is on the back wheel and 40% on the front wheel. The coefficient of friction between the tires and the road is 0.8. What is the greatest acceleration she can hope to achieve?
Whilst riding at 6ms^(-1), she applies both brakes to stop the wheels rotating. In what distance will she come to a stop?
Newtons second law
The Attempt at a Solution
I think the friction force of the back wheel will be the forward force of the bicycle so
0.48R=75a ,i dont consider the frictional force of the front wheel ?
I have no idea for the next.