Newton's Second Law

  • Thread starter Momentum09
  • Start date
  • #1
71
0
Can somebody please give me hints as to how to approach this problem?

Three blocks are in contact with each other on a frictionless horizontal surface. [order: 2.8kg, 6kg, 7.7kg] A 667 N horizontal force is applied to the block with mass of 2.8kg. What is the net force on the block with mass 2.8kg? What is the resultant force on the block with mass 6kg?

Thank you!
 

Answers and Replies

  • #2
143
0
Whats similar about all three blocks? They all have the same acceleration. So
F=ma ---> [tex]\frac{F}{block_{1}+block_{2}+bock_{3}}=a[/tex]
You can use that information to find the answers to your other questions.
 
  • #3
71
0
Thanks!
And to find the magnitude of the force between the block with mass 6kg and 7.7kg, do I subtract the net force for 6kg from that of 7.7kg?
 

Related Threads on Newton's Second Law

  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
20
Views
899
  • Last Post
Replies
3
Views
982
  • Last Post
Replies
8
Views
939
  • Last Post
Replies
7
Views
1K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
1
Views
6K
  • Last Post
Replies
4
Views
4K
Top