• Support PF! Buy your school textbooks, materials and every day products Here!

Newtons second law

  • Thread starter Niles
  • Start date
  • #1
1,868
0

Homework Statement


Hi

Say I am given Newtons second law in this form:

[tex]
\frac{{d^2 x}}{{dt^2 }} + \gamma \frac{{dx}}{{dt}} + \omega _0^2 x + const = 0
[/tex]

I know the physical interpretation of all terms except the last one, i.e. the constant. Does this go into the restoring-force term, and hence create an un-symmetric potential?
 

Answers and Replies

  • #2
108
0
You might sometimes see it as mx''+bx'+kx=0, for a harmonic oscillator under friction. Since you have x''+nx'+w2x+C_=0, you again have a harmonic oscillator under friction (n=b/m, w2=k/m), but, as you might recognize if you moved C_ to the right-hand-side, you have an oscillator under forced resonance.
 
  • #3
ehild
Homework Helper
15,406
1,810
When C is a constant this is a damped oscillator that oscillates around x=-C/w instead of x=0. Like a mass hanging on a spring.

ehild
 

Related Threads for: Newtons second law

  • Last Post
Replies
3
Views
880
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
8
Views
815
  • Last Post
Replies
20
Views
726
  • Last Post
Replies
0
Views
1K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
7
Views
1K
  • Last Post
Replies
5
Views
1K
Top