Newton's Third Law of toboggans

In summary, three toboggans with masses of 42kg, 30kg, and 24kg are attached to each other with ropes. A force of 145 N[forward] is pulling the first toboggan. Assuming a frictionless surface, the acceleration of all three toboggans can be calculated using the formula F(net external) = M(total) a(centre of mass). The tension in the rope between the first and second toboggan can be found by considering the first toboggan as a system and using the formula 145 - T = 42a, where T is the tension force and a is the acceleration calculated in part (a). Similarly, the tension in the connection between the second and third
  • #1
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Three toboggans are attached to each other with ropes. A force of 145 N[forward] is pulling the first toboggan, which has a mass of 42kg. A second toboggan, with a mass of 30kg, is attached to the first second toboggan. A third toboggan with a mass of 24kg, is attached to the second toboggan. Assume that the surface is frictionless.
a) What is the acceleration of all three toboggans?
b) Calculate the tension in the rope between the first toboggan and the second toboggan.
c) Calculate the tension in the rope between the second toboggan and the third toboggan.

i would like to verify my answers and if you guys could show hwo you do b and c step by step or explain it, it would help
B) 81.54N
C) 36.24N


Please and thank you :D
 
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  • #2
Your answers are correct.

It is all a matter of how you define the "system" that you're looking at. For any system, we have:

F(net external) = M(total) a(centre of mass)

For part (a), you can define the system as including all three toboggans. The tension forces are internal forces, and the only external force is the 145 N force. The total mass is the sum of the three masses of the toboggans making up the system.

For part (b), for example, take instead just the first toboggan as the system. There are two external forces on this system: the 145 N force and the tension force from the connection to the 2nd toboggan. So, for this system:

145 - T = 42a

You already know a from part (a), so you can solve for T.

It is also possible, for example, to consider a system consisting of two of the three toboggans.

Hope that helps.
 
  • #3
yes it does, i liek to think of things logically (it makes it easier to remember what forumla to use and stuff) so, the tension in the connection between the first and 2nd toboggan would be higher than the last and 2nd one because there is more weight being pulled... correct?
 

What is Newton's Third Law of Toboggans?

Newton's Third Law of Toboggans states that for every action, there is an equal and opposite reaction. This means that when a toboggan pushes against the ground, the ground will push back with an equal force in the opposite direction.

How does Newton's Third Law of Toboggans apply to tobogganing?

When a person sits on a toboggan and pushes off the ground, the toboggan will accelerate forward due to the force applied by the person. However, the ground will also push back with an equal force, which allows the toboggan to move forward.

Can Newton's Third Law of Toboggans be observed in other scenarios?

Yes, Newton's Third Law of Toboggans can be observed in various scenarios, such as a person walking on the ground, a bird flying in the air, or a car driving on the road. In each case, there is an equal and opposite reaction to the force applied.

What is the significance of Newton's Third Law of Toboggans in science?

Newton's Third Law of Toboggans is significant because it helps explain the concept of forces and motion. It also plays a crucial role in understanding how objects interact with each other and their surroundings.

Is it possible to break or defy Newton's Third Law of Toboggans?

No, it is not possible to break or defy Newton's Third Law of Toboggans. This law is a fundamental principle of physics and has been consistently observed and proven through experiments and real-life scenarios.

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