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Newton's third law Problem

  • #1
question is 29./ about bob and throwing his rock, I have found a./ (225N) easily enough it is b./ which i cannot figure out. Im assuming that it is a newtonian action-reaction pair and that the rock pushes back on bob at 225N as well, which would mean Bob's acceleration would be 3.0ms/s^2. But how do i found his take off speed (I'm asuming kinematics but not sure how with missing variables)??


Answer is 0.2m/s which i cant understand??
 

Answers and Replies

  • #2
265
0
Could you post the complete question.
 
  • #4
265
0
The simplest way to do this is with conservation of momentum.
 
  • #5
thanks, didnt think of that
 

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