Niobium's 5s subshell unfilled?

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In summary, Niobium has an unusual electron configuration due to its unique energy differences between the 4d and 5s subshells, which result in a lower energy state for the 5s2 4d3 configuration compared to the expected 5s1 4d4 configuration. There is no clear set of rules that can account for all exceptions in electron configurations, and the exact energy calculations for each state are complex.
  • #1
DocZaius
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Niobium: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1 4d4

I have been learning a little about electron configuration rules and from what I have read online, I cannot understand why Niobium doesn't fill its 5s subshell before moving on to the 4d subshell.

Wikipedia says "A d subshell that is half-filled or full (ie 5 or 10 electrons) is more stable than the s subshell of the next shell. This is the case because it takes less energy to maintain an electron in a half-filled d subshell than a filled s subshell."

That's all well and good but withholding an electron from the 5s subshell in this case doesn't give the 4d subshell 5 electrons! So what's the actual reason for the 5s subshell not being filled?
 
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  • #2
Niobium is just a little weird. The ordering rules used for determining any electron configuration must be understood as nothing more than useful rules of thumb, but there are several exceptions, and Nb is one of them.

For a somewhat unilluminating reason with no predictive power, consider that 5s2 4d3 may be more energetic than 5s1 4d4 because the energy savings from dropping a 4d electron into a 5s sub-shell does not make up for the energy gain in having two spin-paired electrons in the same sub-shell. Clearly, this is not the case in either V or Ta, so it must be that the energy difference between 4d and 5s is smaller than the energy difference between 3d and 4s or between 5d and 6s.
 
  • #3
Gokul43201 said:
Niobium is just a little weird. The ordering rules used for determining any electron configuration must be understood as nothing more than useful rules of thumb, but there are several exceptions, and Nb is one of them.

For a somewhat unilluminating reason with no predictive power, consider that 5s2 4d3 may be more energetic than 5s1 4d4 because the energy savings from dropping a 4d electron into a 5s sub-shell does not make up for the energy gain in having two spin-paired electrons in the same sub-shell. Clearly, this is not the case in either V or Ta, so it must be that the energy difference between 4d and 5s is smaller than the energy difference between 3d and 4s or between 5d and 6s.

Is there a clear set of rules (no matter how complicated) that actually accounts for all of these exceptions and is compatible with all the elements? If so, can it be found on the web?
 
  • #4
Oh no, you really don't want to go there. Or at least not before finishing a master's degree in Theoretical Chemistry or Particle Physics or the like. "No matter how complicated" would include the generation of a generalized wave function including the core and all electrons for all elements (anything less is an approximation and therefore will generate exceptions). It may well never have been done so far.

Want for a clear set of rules that needs no exceptions is a common source of frustration for those in introductory chemistry. All sets of rules (including, but by no means limited to, the rules for determining electron configurations) that are commonly taught in chemistry are based on one or the other set of simplifications, so they are never good for all cases. The real (quantum mechanical) situation is almost invariably so complex that simple rules do not exist. One who can accept that can go on to become a great chemist. One who cannot will eventually turn away from the subject. Sad, but true
 
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  • #5
This is an old thread, but as it was already revived - there is a simple rule. It states that ground state configuration is that of the lowest energy. It is calculation of the exact energy for any possible state that is tricky.
 
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  • #6
  • #7
More or less the same you have said :smile: "Rule of lowest energy" is simple to state and understand, but of no use in practice, as it leads to hard to solve PDE. But the principle is simple.
 
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1. What is the electron configuration of Niobium's 5s subshell?

The electron configuration of Niobium's 5s subshell is 5s1. This means that it has one electron in its 5s orbital.

2. Why is Niobium's 5s subshell unfilled?

Niobium's 5s subshell is unfilled because it follows the Aufbau principle, which states that electrons fill orbitals in order of increasing energy. The 5s subshell is at a higher energy level than the 4d subshell, so it is filled after the 4d subshell is filled.

3. What is the significance of Niobium's 5s subshell being unfilled?

The unfilled 5s subshell in Niobium is significant because it allows for the element to form multiple oxidation states. This is because the 5s electron can easily be lost or gained, leading to different configurations with different numbers of electrons in the outermost shell.

4. How does the unfilled 5s subshell affect the properties of Niobium?

The unfilled 5s subshell in Niobium affects its properties by making it a good conductor of electricity and heat. This is because the 5s electron is not tightly bound to the nucleus and can easily move around, allowing for the flow of electricity and heat. It also contributes to the element's high melting and boiling points.

5. Can the 5s subshell in Niobium be filled?

Yes, the 5s subshell in Niobium can be filled under certain conditions. For example, when Niobium forms an ion, it can lose its 5s electron and become a positively charged ion with a filled 5s subshell. Additionally, in certain chemical reactions, Niobium can bond with other elements and fill its 5s subshell in order to achieve a more stable electron configuration.

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