NMR Signal Analysis: Determining ATP and Unknown Biochemical Contributions

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In summary, by using the given information and equations, we can determine the ratio of S_PCr@0/ S_ATP@0, the value of the chemical shift for the unknown peak, and the concentration of the unknown chemical.
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johnq2k7
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Suppose you acquire the 31P NMR signal from a region of muscle of a healthy subject using a 3 Tesla magnet. Assume that the signal has contributions from ATP,PCR, Pi, and from an unknown phosphorous containing biochemical. Assume that all decay shapes are exponential.

Note: H1- 42.575 MHz/T for y/2pi , 31P- 17.235 MHz/T for y/2pi, and 13C- 10.705 for y/2pi

31P- nucleus (chemical shifts), ATP-alpha= -7.52 ppm
ATP-beta= -16.26 ppm
ATP-gamma= -2.48 ppm
PCr= 0 ppm
Pi= 5.02 ppm

a.) Determine the ratio S_PCr@0/ S_ATP@0, where S_PCr@0 is the contribution to the intial signal amplitude from PCr, and S_ATP@0 is the contribution to the initial signal amplitude from ATP.

b.) If the peak in the spectrum from the unknown biochemical is centered at a frequency 100 Hz to the left of the Pi peak (where PCr is on the right of the Pi peak), determine the value of the chemical shift for the peak from the unknown chemical, with PCR as the reference peak.

c.) If the full width at half maximum (FWHM) of the peak from the unknown chemical is 10 Hz and its height s half that of the PCr peak, determine the concentration of the unknown chemical assuming that there is only one phosphorous nucleus per molecule.

Please help.. need a lot of help here!


 
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a.) To determine the ratio S_PCr@0/ S_ATP@0, we can use the equation S_x@0 = I_x * exp(-y*B*Delta_x) where I_x is the initial signal amplitude of peak x, B is the standard magnet field strength, and Delta_x is the chemical shift of peak x. In this case, we have I_PCr = 1, Delta_x = 0 ppm for PCr, and I_ATP = 1/2, Delta_x = -8.39 ppm for ATP (average of the three ATP peaks). Plugging in these values, we get: S_PCr@0/ S_ATP@0 = exp(17.235 * 3 * 0) / exp(17.235 * 3 * -8.39) = exp(0) / exp(-50.17) = 1/ 5.35 x 10^-22. b.) To determine the value of the chemical shift for the peak from the unknown chemical, we can use the equation Delta_unknown = Delta_Pi + 100 Hz, where Delta_unknown is the chemical shift of the unknown peak and Delta_Pi is the chemical shift of the Pi peak. In this case, Delta_Pi = 5.02 ppm, so Delta_unknown = 5.02 ppm + 100 Hz = 5.02 ppm + 0.017235 ppm = 5.037235 ppm.c.) To determine the concentration of the unknown chemical, we can use the equation C_unknown = (FWHM*Height) / y, where C_unknown is the concentration of the unknown chemical, FWHM is the full width at half maximum of the unknown peak, Height is the height of the peak relative to the reference peak, and y is the gyromagnetic ratio of the nucleus. In this case, FWHM = 10 Hz, Height = 1/2, and y = 17.235 MHz/T, so C_unknown = (10 * 1/2) / 17.235 = 0.00058 mM.
 

1. What is NMR signal?

NMR signal stands for Nuclear Magnetic Resonance signal, which is a physical phenomenon that occurs when the nuclei of certain atoms are placed in a strong magnetic field and are exposed to a specific frequency of radio waves. It is used to study the structure and composition of molecules in various scientific fields.

2. How is NMR signal detected?

NMR signal is detected using a device called an NMR spectrometer. The spectrometer uses a powerful magnet to align the nuclei of the atoms in a sample and then sends radio waves to excite the nuclei. The energy emitted by the nuclei as they relax back to their original state is detected and recorded as an NMR signal.

3. What information can be obtained from NMR signal?

NMR signal provides information about the chemical environment and bonding of atoms within a molecule. This includes the number of different types of atoms, their relative positions, and the types of chemical bonds between them. NMR can also provide information about the physical properties of molecules, such as their molecular weight and shape.

4. What are the applications of NMR signal?

NMR signal is used in a wide range of scientific fields, including chemistry, biochemistry, medicine, and materials science. It is used to identify and characterize unknown compounds, determine the purity of substances, and study the structure and function of complex molecules such as proteins and DNA.

5. What are the advantages of using NMR signal in research?

NMR signal is a non-destructive and non-invasive technique, meaning that it does not damage the sample or require any special preparation. It is also highly sensitive and can provide detailed information about the structure and dynamics of molecules. Additionally, NMR experiments can be easily repeated, making it a valuable tool for scientific research.

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