- #1
jackxx
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[tex]\nabla \cdot B=0,[/tex]
so [tex]\int\nabla \cdot B dv=0,[/tex]
then [tex]\int B \cdot \widehat{n}da=0,[/tex]
let [tex]B=\nabla \times A,[/tex]
then [tex]\int\nabla \times A \cdot \widehat{n}da=0,[/tex]
thus [tex]A=\nabla\varphi[/itex], thus [tex]B=\nabla \times A=\nabla \times\nabla\varphi=0[/tex]
I know something is wrong with that but I am not sure what it is any ideas?
so [tex]\int\nabla \cdot B dv=0,[/tex]
then [tex]\int B \cdot \widehat{n}da=0,[/tex]
let [tex]B=\nabla \times A,[/tex]
then [tex]\int\nabla \times A \cdot \widehat{n}da=0,[/tex]
thus [tex]A=\nabla\varphi[/itex], thus [tex]B=\nabla \times A=\nabla \times\nabla\varphi=0[/tex]
I know something is wrong with that but I am not sure what it is any ideas?
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