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Noble Gas Configuration

  1. Oct 30, 2006 #1
    Could someone please help me finish the nobel gas configuration for uranium? I get as far as [Rn] 7s2, but I can't figure out what goes next.
     
  2. jcsd
  3. Oct 30, 2006 #2
  4. Oct 30, 2006 #3
    What is the reason for this structure? I assume the 5F3 is more stable than 5f4, kind off like the half filled 3d5 taking preference.

    On a related note I was looking here http://www.chemguide.co.uk/atoms/properties/ionstruct.html#top, and intuitively I'd though of thought when Fe beomces Fe3+ that a 3d atom would be lost before the 4s atom since that 3d54s2, is more stable than 3d64d1?

    note: been a while since I did any chemistry.
     
  5. Oct 30, 2006 #4
    Ok I see what my mistake was...I had the first part right, but then I kept putting 5f before 6d. In this case, 5f goes afterward, so the configuration is actually [Rn] 7s2 6d1 5f3.

    Thanks for the help. :)
     
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