- #1

Rozenwyn

- 31

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http://img209.imageshack.us/img209/8136/423ky7.jpg [Broken]

I have trouble getting the correct answers.

I tried:

At node V1 [tex]\ i_1 + \frac{v_2-v_1}{5} = \frac{v_1}{20} \ \longrightarrow[/tex] Solve for [tex]i_1[/tex]

ok let's try.

[tex] i_1 + \frac{15-4}{5} = \frac{4}{20}[/tex]

[tex] i_1 = \frac{1}{5} - \frac{11}{5} [/tex]

[tex] i_1 = \frac{-10}{5} = -2A[/tex]

@Cornea: Indeed, the equations seem to be correct. *bangs head to the table.* Can't believe a sign error could waste 2 hrs of my life. Hmmm, need more sleep ... more sleep.

Then;

Ar node V2 [tex]\ \frac{v_2-v_1}{5} + \frac{v_2-v_3}{15} = i_2 \ \longrightarrow[/tex] Solve for [tex]i_2[/tex]

When I solve for [tex]i_1, \ i_2[/tex] I get wrong answers.

I have trouble getting the correct answers.

I tried:

At node V1 [tex]\ i_1 + \frac{v_2-v_1}{5} = \frac{v_1}{20} \ \longrightarrow[/tex] Solve for [tex]i_1[/tex]

ok let's try.

[tex] i_1 + \frac{15-4}{5} = \frac{4}{20}[/tex]

[tex] i_1 = \frac{1}{5} - \frac{11}{5} [/tex]

[tex] i_1 = \frac{-10}{5} = -2A[/tex]

@Cornea: Indeed, the equations seem to be correct. *bangs head to the table.* Can't believe a sign error could waste 2 hrs of my life. Hmmm, need more sleep ... more sleep.

Then;

Ar node V2 [tex]\ \frac{v_2-v_1}{5} + \frac{v_2-v_3}{15} = i_2 \ \longrightarrow[/tex] Solve for [tex]i_2[/tex]

When I solve for [tex]i_1, \ i_2[/tex] I get wrong answers.

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