1. Apr 14, 2009 #1

   Nyasha

   

   Guys l would like to know how does the the voltage at node D become :
   
   Vd=-(Vc-Va)=Va-Vc

    

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   Nyasha, Apr 14, 2009
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3. Apr 15, 2009 #2

   The Electrician

   

   Gold Member

   Calculate ix = (VC-VA)/2. You see why this is, I hope. Ask if you don't.
   
   Then the dependent source feeding VD has a voltage VD =-2*ix. Substituting what we calculated for ix above, we have VD = -2*ix = -2*(VC-VA)/2 = VA-VC.

    

   The Electrician, Apr 15, 2009

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