Guys l would like to know how does the the voltage at node D become : Vd=-(Vc-Va)=Va-Vc
Apr 14, 2009 #1 Nyasha 127 0 Guys l would like to know how does the the voltage at node D become : Vd=-(Vc-Va)=Va-Vc Attachments Untitled.jpg 14 KB Views: 242
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Apr 15, 2009 #2 The Electrician Gold Member 1,246 152 Calculate ix = (VC-VA)/2. You see why this is, I hope. Ask if you don't. Then the dependent source feeding VD has a voltage VD =-2*ix. Substituting what we calculated for ix above, we have VD = -2*ix = -2*(VC-VA)/2 = VA-VC.
Calculate ix = (VC-VA)/2. You see why this is, I hope. Ask if you don't. Then the dependent source feeding VD has a voltage VD =-2*ix. Substituting what we calculated for ix above, we have VD = -2*ix = -2*(VC-VA)/2 = VA-VC.
