Guys l would like to know how does the the voltage at node D become : Vd=-(Vc-Va)=Va-Vc
Apr 14, 2009 #1 Nyasha 127 0 Guys l would like to know how does the the voltage at node D become : Vd=-(Vc-Va)=Va-Vc Attachments Untitled.jpg 14 KB Views: 266
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Related Engineering and Comp Sci Homework Help News on Phys.org Spacewalking astronauts prep station for new solar wings Roman chariot unearthed 'almost intact' near Pompeii When using pyrite to understand Earth's ocean and atmosphere: Think local, not global
Apr 15, 2009 #2 The Electrician Gold Member 1,282 168 Calculate ix = (VC-VA)/2. You see why this is, I hope. Ask if you don't. Then the dependent source feeding VD has a voltage VD =-2*ix. Substituting what we calculated for ix above, we have VD = -2*ix = -2*(VC-VA)/2 = VA-VC.
Calculate ix = (VC-VA)/2. You see why this is, I hope. Ask if you don't. Then the dependent source feeding VD has a voltage VD =-2*ix. Substituting what we calculated for ix above, we have VD = -2*ix = -2*(VC-VA)/2 = VA-VC.
