- #1

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## Homework Statement

Refer Attachment

## Homework Equations

## The Attempt at a Solution

I have drawn the current direction in green. Are there any rules regarding the direction of the current?

I am at a bit of a loss regarding the horizontal current through the middle. The best I could come up with is: (V1-V3)/6-V3/3 that is through the 5i voltage source and (V1-V3)/6-V3/3-V2/4 through the 10V voltage source.

For the 10V supernode I have the following equation from KCL: 6V1+6V2+4V3=0. KVL: V1=10+v2.

For the 5i supernode I have the following equation from KVL:V3-V2-5i=0 and i=V1/2.

Therefore V3-V2-5V1/2=0.

Using these equations I get V1=3.85V, V2=-6.15V and V3=3.45V.

Any help would be appreciated.