 7
 0
1. Homework Statement
(I have attached a picture of the circuit)
Using node voltage analysis in the circuit, find the current i drawn from the independent voltage source. Let V=3V, R1=1/2, R2=1/2, R3=1/4, R4=1/2, R5=1/4, I=0.5.
2. Homework Equations
I=V/R
3. The Attempt at a Solution
I haven't seen one like this w/ the independent voltage source, is it solved the same way? I tried to perform KCL at each node and got:
node 1: (Vv1)/R1 + v1/R2 + (v1v2)/R3 = 0
node 2: (v1v2)/R3 + (v3v2)/R4 = I
node 3: (v3v2)/R4 + v3/R5 = 0
When I substituted for V, I, R1, R2, R3, R4 and R5 and entered in the matrix I got:
v1=6.375
Then I related i=(Vv1)/R1. I got an answer of 18.75 A. I thought the answer maybe sounded high and was wondering if I had messed up somewhere.
(I have attached a picture of the circuit)
Using node voltage analysis in the circuit, find the current i drawn from the independent voltage source. Let V=3V, R1=1/2, R2=1/2, R3=1/4, R4=1/2, R5=1/4, I=0.5.
2. Homework Equations
I=V/R
3. The Attempt at a Solution
I haven't seen one like this w/ the independent voltage source, is it solved the same way? I tried to perform KCL at each node and got:
node 1: (Vv1)/R1 + v1/R2 + (v1v2)/R3 = 0
node 2: (v1v2)/R3 + (v3v2)/R4 = I
node 3: (v3v2)/R4 + v3/R5 = 0
When I substituted for V, I, R1, R2, R3, R4 and R5 and entered in the matrix I got:
v1=6.375
Then I related i=(Vv1)/R1. I got an answer of 18.75 A. I thought the answer maybe sounded high and was wondering if I had messed up somewhere.
Attachments

4.5 KB Views: 224