Non Flow Energy Equation

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febbie22
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Homework Statement


1 kg of air at a pressure of 100 kPa occupying a volume of 0.025 m3 is
compressed to a pressure of 150 kPa according to the law
pv1.3 = constant.

Determine:
(i) Work done on or by the gas; (6)
(ii) Change in internal energy of the gas; (6)
(iii) Heat received or rejected by the gas; (4)

Take Cv = 0.718 kJ/kg K, Cp = 1.005 kJ/kg K


Homework Equations



In attachment the password is exam

The Attempt at a Solution



I think i can do the first part fine:

W= ((100*10^3) * 0.025 - (150*10^3) * 0.0183) / -0.3
= 816.67

Its the second part that i don't get as it asks for the change in internal energy before the heat received

is there a equation to calculate the internal energy as there is one here:

U2-U1= Q + W

but i would need to work out Q before U2-U1

any help would be much appreciated
 

Attachments

  • EN2702 THERMOFLUIDS Jan 10.pdf
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Answers and Replies

  • #2
haruspex
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The internal energy of an ideal gas is CvnT=CvPV/R.
 

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