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febbie22
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Homework Statement
1 kg of air at a pressure of 100 kPa occupying a volume of 0.025 m3 is
compressed to a pressure of 150 kPa according to the law
pv1.3 = constant.
Determine:
(i) Work done on or by the gas; (6)
(ii) Change in internal energy of the gas; (6)
(iii) Heat received or rejected by the gas; (4)
Take Cv = 0.718 kJ/kg K, Cp = 1.005 kJ/kg K
Homework Equations
In attachment the password is exam
The Attempt at a Solution
I think i can do the first part fine:
W= ((100*10^3) * 0.025 - (150*10^3) * 0.0183) / -0.3
= 816.67
Its the second part that i don't get as it asks for the change in internal energy before the heat received
is there a equation to calculate the internal energy as there is one here:
U2-U1= Q + W
but i would need to work out Q before U2-U1
any help would be much appreciated