Ethanol (bp= 78° C) and water (bp= 100°C) form an azeotropic mixture at 4% water ans temperature 65°C.
what is obtained in the residue and the distillate if:
i) 3% water is used
ii) 20% water is used
The Attempt at a Solution
I know that the distillate would always be the azeotrope but i'm not sure how the %change in water affects the residue.
I assumed that since the azeotropic mixture is formed at 4% then the residue would be ethanol and at 20% the residue would be water.
can someone please explain this...I know my reasoning is wrong.