Non- Ideal Mixtures- positve deviation from Raoult's Law

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Homework Statement


Ethanol (bp= 78° C) and water (bp= 100°C) form an azeotropic mixture at 4% water ans temperature 65°C.

what is obtained in the residue and the distillate if:
i) 3% water is used
ii) 20% water is used

The Attempt at a Solution



I know that the distillate would always be the azeotrope but i'm not sure how the %change in water affects the residue.

I assumed that since the azeotropic mixture is formed at 4% then the residue would be ethanol and at 20% the residue would be water.

can someone please explain this...I know my reasoning is wrong.
 

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