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Non-parallel Plate Capacitor

  1. Feb 14, 2008 #1
    1. The problem statement, all variables and given/known data
    A capacitor has square plates, each of side a, making an angle theta with eachother. Shown that for small theta the capacitance is given by: C = [(epsilon)(a^2)/d][1-(a(theta)/2d].

    2. Relevant equations
    C = q/V
    gauss' law

    3. The attempt at a solution
    I see how you can divide up the strip into N segments each with length a/N. But how do u get the capacitance for each strip to be C = (epsilon)a(deltax)/y ? I know how to do the rest and I know for sure that that's the right way to do it, but how do u get the capacitance for each strip?)
  2. jcsd
  3. Feb 14, 2008 #2
    See that C = [tex]\epsilon[/tex]*S/d, in your case for each strip S = a*dx and d = y.
  4. Mar 20, 2011 #3
    I'm also troubled with this question, I know it has been a long time, but maybe one of you can explain me the answer?

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