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Non-Riemannian Geommetry ?

  1. Feb 24, 2010 #1
    Non-Riemannian Geommetry ??

    in Riemann Geommetry one needs a metric to define a distance so

    [tex] ds^{2}= g_{i,j}dx^{i}dx^{j} [/tex] is a Bilinear form

    the idea is can this be generalized to a non-metric Geommetry ? i mean, you define the distance via a function F so

    [tex] ds^{2}= F(x_{i} , x_{j},dx_í} , dx_{j} ) [/tex]

    so this time we do not have a Bilinear form or we do not have or depend on a metric [tex] g_{i,j} [/tex] is this the Non-Riemannian Geommetry ??
  2. jcsd
  3. Feb 24, 2010 #2


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    Re: Non-Riemannian Geommetry ??

    The only example I know is Finsler geometry.
  4. Feb 24, 2010 #3

    Ben Niehoff

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    Re: Non-Riemannian Geommetry ??

    The word "Riemannian" also usually implies that the quadratic form g is positive definite. Then Lorentz metrics constitute "non-Riemannian" geometry, but since changing the signature is not too big of a change, usually we just say "pseudo-Riemannian".

    As Quasar mentions, Finsler geometry is another option. Finsler geometry is to Riemannian geometry as Banach space is to Hilbert space. That is, in Finsler geometry, you define a norm, but not an inner product. The norm satisfies the triangle inequality, but there is no notion of angles. There are some other properties that I can't remember.
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