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noboost4you
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I along with a buddy of mine in the same course have been trying to figure out the following question. We spent at least an hour and a half to two hours and nothing makes sense. Any help would be greatly appreciated.
Here's the question as it's written:
One way to measure the acceleration of your car is to see how far a pendulum swings from the vertical. That is why so many highly intelligent drivers have objects hanging from their rear-view mirrors. You notice that when you accelerate, the fuzzy dice (0.25 kg) you have hanging swings 15 degrees from the vertical. Find the acceleration that produces this amount of deflection.
We began by drawing a picture of a 15 degree angle with a mass at the end of the hypothesis. We've never seen a problem like this in our class before.
If it has acceleration, it is not in equilibrium. So we looked through the whole chapter and this is what we discovered; "If an object is not in equilibrium, then Newton's second law must be used to account for acceleration." And they give us these two equations: (SUM)Fx=m(ax) and (SUM)Fy=m(ay).
We've done problems similar to this finding forces using the x- and y-components, but we're drawing a blank here.
Any help is great appreciated. TIA, Bryan
Here's the question as it's written:
One way to measure the acceleration of your car is to see how far a pendulum swings from the vertical. That is why so many highly intelligent drivers have objects hanging from their rear-view mirrors. You notice that when you accelerate, the fuzzy dice (0.25 kg) you have hanging swings 15 degrees from the vertical. Find the acceleration that produces this amount of deflection.
We began by drawing a picture of a 15 degree angle with a mass at the end of the hypothesis. We've never seen a problem like this in our class before.
If it has acceleration, it is not in equilibrium. So we looked through the whole chapter and this is what we discovered; "If an object is not in equilibrium, then Newton's second law must be used to account for acceleration." And they give us these two equations: (SUM)Fx=m(ax) and (SUM)Fy=m(ay).
We've done problems similar to this finding forces using the x- and y-components, but we're drawing a blank here.
Any help is great appreciated. TIA, Bryan