- #1
unseenoi
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hello can someone explain how to guess the yp for this Non-homogeneous differential equation
y'' - 2y' + y = te^t
characteristic polynomial: (y - 1)^2 so the characteristic roots are: y1=y2= 1
c1 and c2 are constant
for yh = (c1)e^t + (c2)te^t
please explained how to guess for te^t
y'' - 2y' + y = te^t
characteristic polynomial: (y - 1)^2 so the characteristic roots are: y1=y2= 1
c1 and c2 are constant
for yh = (c1)e^t + (c2)te^t
please explained how to guess for te^t