# Nonlinear ODE system

1. Jun 17, 2010

### zokomoko

Given the ODE system:
v' = u(u2-1)
u' = v-u

Define w=u2+v2. Compute w'.
Find the largest radius R for which u2+v2<R so that the if the solution curve (u,v) is inside that circle the solution tends to (0,0) as t--> +$$\infty$$

Any guidance would be appriciated !

2. Jun 17, 2010

### Dickfore

First, use the chain rule of differentiation and the expressions for $u'$ and $u'$ to find $w'$. Please show us the result of your work.

3. Jun 17, 2010

### zokomoko

sorry I forgot to mention I only had difficulty with the second part of the question.

W'= 2uu'+2vv'=2u[v-u]+2v[u(u2-1)]=2vu-2u2+2vu3-2uv
W' = -2u2+2vu3

I think (but perhaps I'm mistaken) W is suppose to be a lyoponouv function and I'm suppose to find the radius R in which W is monotically decreasing thus proving that the origin is stable fixed point (so every solution tends to the origin) in the said circle.

so my problem is the second part, how to find the radius R in which W is monotically decreasing, if what I've written earlier is even correct..

4. Jun 17, 2010

### elibj123

What is the condition so W(t) would monotonically decrease?

5. Jun 17, 2010

### zokomoko

W'=-2u2+2vu3<0

v>0, u<0 no problem
v<0, u>0 no problem

u,v both positive or both negitive are problematic because W' can be positive in those regions, no ?

6. Jun 17, 2010

### Dickfore

This is not correct.

7. Jun 17, 2010

### zokomoko

8. Jun 17, 2010

### elibj123

Simplify the inequality you got to get a simpler relation.

9. Jun 17, 2010

### Dickfore

You can factorize the inequality you got. Then use the following rule:

$$A B < 0 \Leftrightarrow \left[\begin{array}{l} \left\{\begin{array}{l} A > 0 \\ B < 0 \end{array}\right. \\ \left\{\begin{array}{l} A < 0 \\ B > 0 \end{array}\right. \end{array}\right.$$