1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Nonuniform Circular Motion

  1. Sep 30, 2007 #1
    A roller-coaster car has a mass of 500 kg when fully loaded with passengers. (a) If the vehicle has a speed of 20.0 m/s at point A, what is the force exerted by the track on the car at this point? (b) What is the maximum speed the vehicle can have at point B and still remain on the track?

    [​IMG]



    Is the answer to (b) dependent on the tangential acceleration?


    For part (a), I found the force exerted on the car by the track to be
    m( g - ( v^2 ) / R1 ) = 500( 9.8 - ( 20.0 / 10.0 ) ) = 3900 N.

    Then for part (b), I have
    0 = mg( ( vmax^2 ) / ( R2 * g ) - cos 0 ) -> vmax = ( g * R2 )^( 1 / 2 ) =
    ( 9.8 * 15 )^( 1 / 2 ) = 12.1 m/s.

    Am I in the ball-park?
     
  2. jcsd
  3. Sep 30, 2007 #2

    lightgrav

    User Avatar
    Homework Helper

    well, your first statement implies that if it was moving FASTER at A,
    the track would push LESS hard ... by 100 m/s it wouldn't even NEED a track.

    mg is a real Force, downward (left side of eqn)
    . . . . v^2/R is an acceleration (on right side of eqn)
    . . . . F_track is a real Force (on the left side of eqn)

    same sign mistake in "2"
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Nonuniform Circular Motion
Loading...