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I Norm of the Laplacian

  1. Mar 5, 2017 #1
    Let ##(M,g)## a manifold with a Levi-Civita connection ## \nabla ## and ##X## is a vector field.
    What is the formula of ## | \nabla X|^2 ## in coordinates-form?

    I know that ##|X|^2= g(X,X)## is equivalent to ## X^2= g_{ij} X^iX^j## and ##\nabla X## to ##\nabla_i X^j = \partial_i X^j + \Gamma^j_{il} X^k ## but I can't use these to ## | \nabla X|^2 ##.
     
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  3. Mar 5, 2017 #2

    Orodruin

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    What do you mean by ##|\nabla X|^2##? The object ##\nabla X## is a type (1,1) tensor and if you want to compute its norm you need to define it.
     
  4. Mar 5, 2017 #3
    I am confused with the norms and the covariant derivatives. I know that ##||A||^2 = A_{ij} A^{ij}= g_{ik} g_{jl} A^{kl} A^{ij}## for a (0-2) tensor.

    So if ##\nabla X## is ##\nabla_i X^j = \partial_i X^j + \Gamma^j_{il} X^l ##, is

    ## | \nabla X|^2 ## equal to ## (\nabla_i X^j) (\nabla_j X^i) ## ?
     
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