- #1

- 281

- 0

Hi, I have 2 problems I would like some help. It is about normal distribution(probability)

**PROBLEM 1: Extruded plastic rods are automatically cut into lenghts of 6 inches. Actual lengths are normally distributed about a mean of 6 inches and their standard deviation is 0.06 inch.**

1- what proportion of the rods have lenghts that are outside the tolerance limits of 5.9 and 6.1 inches?

1- what proportion of the rods have lenghts that are outside the tolerance limits of 5.9 and 6.1 inches?

Here I did:

p=F((6.1-6)/0.06)- F((5.9-6)/0.06)= F(1.67)-F(-1.67)=0.9525-0.0475=0.905

P(outside tolerance)=1-0.905=0.095

**2- To what value does the standard deviation needs to be reduce if 99% of the rods must be within the tolerance?**

I can not fin this question.

**PROBLEM 2:**

In a photographic process, the developping time of prints may be looked upon as a random variable having the normal distribution with a mean of 16.28 seconds and a standard deviation of 0.12 second.

- For which value is the probability 0.95 that it will be exceeded by the time it takes to develop one of the prints?

I dont get this one.

In a photographic process, the developping time of prints may be looked upon as a random variable having the normal distribution with a mean of 16.28 seconds and a standard deviation of 0.12 second.

- For which value is the probability 0.95 that it will be exceeded by the time it takes to develop one of the prints?

I dont get this one.

Can I have some help please?