Normal Distribution Question

  • #1

Homework Statement


Suppose that X ~ N(μ,σ). Find a in terms of μ and σ if P(X>a) = 1/3 * P(X ≤a)

Homework Equations




The Attempt at a Solution


1 - P(X ≤a) = 1/3 * P(X ≤a)
3 = 4P(X ≤a)
P(X ≤a) = 3/4

Since x0 = μ + σz0 where x0 and z0 are the same percentile for N(μ,σ) and N(0,1) (respectively), then z0 = 0.67449 (by invNorm(0.75, 0, 1)). It follows that

a = μ + 0.67449σ

I'm not sure if this is the correct method, someone in my class solved it another way and got a different answer, but this seems to make sense to me.

Regards,

Michael
 

Answers and Replies

  • #2
Charles Link
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I agree with your solution. Also please read my last comments on your Poisson distribution problem of last week. I think you'll find them of interest. That was actually the first time I had looked at the Poisson distribution in this much detail, and the two methods of solving the same problem are both quite interesting.
 
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Ray Vickson
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Homework Statement


Suppose that X ~ N(μ,σ). Find a in terms of μ and σ if P(X>a) = 1/3 * P(X ≤a)

Homework Equations




The Attempt at a Solution


1 - P(X ≤a) = 1/3 * P(X ≤a)
3 = 4P(X ≤a)
P(X ≤a) = 3/4

Since x0 = μ + σz0 where x0 and z0 are the same percentile for N(μ,σ) and N(0,1) (respectively), then z0 = 0.67449 (by invNorm(0.75, 0, 1)). It follows that

a = μ + 0.67449σ

I'm not sure if this is the correct method, someone in my class solved it another way and got a different answer, but this seems to make sense to me.

Regards,

Michael

It is the correct method, and the answer is correct.
 

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