Johns24 said:
This link says it requires permission. Post your figure HERE, not there.Johns24 said:
The image is tiny. If I expand it to a decent size the text is illegible.Johns24 said:
The usual one, ΣF=ma.Johns24 said:
I do not believe so.haruspex said:
Right.Johns24 said:
Normal force is the force that a surface exerts on an object in contact with it. It is always perpendicular to the surface and prevents the object from sinking into or passing through the surface.
The normal force is dependent on the mass of an object in the sense that the heavier the object, the greater the normal force required to support it. However, the mass itself does not directly affect the magnitude of the normal force.
No, a massless rope cannot exert a normal force. This is because the normal force is a contact force and a massless rope does not make contact with the object. The tension force in a massless rope is always parallel to the rope and does not have a component perpendicular to the surface to exert a normal force.
The angle of the rope does not directly affect the normal force on the block. As long as the rope is taut and not slack, the normal force remains the same regardless of the angle. However, the angle of the rope can affect the tension force in the rope, which in turn can affect the normal force if the rope is attached to the surface.
The normal force on a block on an inclined plane is always perpendicular to the surface of the plane. The magnitude of the normal force is equal to the component of the weight of the block that is perpendicular to the plane. As the angle of the inclined plane increases, the normal force decreases, eventually becoming zero when the plane becomes vertical.
