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Normal Force

  1. Oct 29, 2006 #1
    I'm trying to think up situations that will help me understand more complicated situations...

    Let's say I have:

    a box
    on a slanted slope
    on a chair
    on the floor

    The floor exerts a normal force on the chair. But, equal to what?

    is it:

    a box [tex]m_{1}gcos\theta[/tex]

    on a slanted slope [tex]m_{2}g[/tex]

    on a chair [tex]m_{3}g[/tex]

    on the floor

    Is it the sum of these?

    Also, would motion of the box along the inclined plane affect the result? It would seem to be "no".
     
  2. jcsd
  3. Oct 29, 2006 #2

    Hootenanny

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    Have you tried drawing a FBD?
     
  4. Oct 29, 2006 #3
    Yes, and it/they were getting complex, so I wanted to get some feedback. I came up with the force exerted down on the chair as having an x component and a y component (different from what I posted). From there I was thinking I could apply that vector to the FBD of the chair and come up with my answer. Is such a "cascading of forces" approach correct?
     
  5. Oct 29, 2006 #4

    Hootenanny

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    Yes, from what I understand you to have described that is correct. Perhaps if you posted you FBD's we could comment further.
     
  6. Oct 29, 2006 #5

    Doc Al

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    Staff: Mentor

    Huh? Are you describing one situation (a box on a chair which is on a slanted slope?) or multiple situations? What are those masses?
     
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