- #1
tiger_striped_cat
- 49
- 1
I am familiar with the normalization
[tex]\int\left|\Psi\right|^{2}dx=1[/tex]
Because we want to normalize the probability to 1. However if a state vector isn't in the x basis and is just a general vector in Hilbert space, we can take the normalization condition to be:
[tex]<\Psi|\Psi>=1[/tex]
Correct? I guess this is making more and more sense to me. I guess I just never thought about it before. But since we can put a completeness relation in the middle of the latter equation then these two are basically equivalent. I guess I'm just having difficultly seeing how probability over all states is 1 in the second case.
Please tell me if this is incorrect.
Thanks!
[tex]\int\left|\Psi\right|^{2}dx=1[/tex]
Because we want to normalize the probability to 1. However if a state vector isn't in the x basis and is just a general vector in Hilbert space, we can take the normalization condition to be:
[tex]<\Psi|\Psi>=1[/tex]
Correct? I guess this is making more and more sense to me. I guess I just never thought about it before. But since we can put a completeness relation in the middle of the latter equation then these two are basically equivalent. I guess I'm just having difficultly seeing how probability over all states is 1 in the second case.
Please tell me if this is incorrect.
Thanks!