I am familiar with the normalization(adsbygoogle = window.adsbygoogle || []).push({});

[tex]\int\left|\Psi\right|^{2}dx=1[/tex]

Because we want to normalize the probability to 1. However if a state vector isn't in the x basis and is just a general vector in Hilbert space, we can take the normalization condition to be:

[tex]<\Psi|\Psi>=1[/tex]

Correct? I guess this is making more and more sense to me. I guess I just never thought about it before. But since we can put a completeness relation in the middle of the latter equation then these two are basically equivalent. I guess I'm just having difficultly seeing how probability over all states is 1 in the second case.

Please tell me if this is incorrect.

Thanks!

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# Homework Help: Normalization conditions in quantum mechanics

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