Normalization of a function

  • #1

Homework Statement



I have normalized the following function:

[tex] Q=\int (1-y^2) dx dy [/tex]

Homework Equations



using the expression for the normalization

[tex] \vert N \vert ^2 \vert \int Q^* Q dx dy \vert^2 =1 [/tex]


The Attempt at a Solution



then I obtained

[tex] \int Q^* Q dx dy = x (y- y^3 /3) [/tex]

therefore

[tex] N = 1/ x (y- y^3 /3) [/tex]

but I am not sure if I have done good.
 

Answers and Replies

  • #2
You normalize functions over regions in space. The normalization factor should not be a function of anything but perhaps the boundary of the region you're examining.

And you either stated your function Q incorrectly or you evaluated the double integral incorrectly. Also you stated your normalization equation wrong, you're doubling up on the squaring.

You need to start over from the beginning.
 

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