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**1. Homework Statement**

In a double-slit experiment, the slits are on the y-axis and the electrons are detected

on a vertical screen. When only slit #1 is open, the amplitude of the wave which

gets through is

[tex] \psi(y,t) = A \exp^{-y^2} \exp^{-i((ky-\omega t)} [/tex]

when only slit #2 is open, the amplitude of the wave which gets through is

[tex] \psi(y,t) = A \exp^{-y^2} \exp^{-i(k+\pi)y-\omega t)} [/tex]

(a) Normalize 1 and 2.

**2. Homework Equations**

Normalization Condition

[tex] \int_{-\infty}^{\infty}\psi*\psi dy = 1 [/tex]

**3. The Attempt at a Solution**

1.

[tex] 1=\int_{-\infty}^{\infty} A (\exp^{-y^2} \exp^{-i((ky-\omega t)}) (\exp^{-y^2} \exp^{i((ky-\omega t)}) dy

[/tex]

[tex]1=A \int_{-\infty}^{\infty} \exp^{-2y^2} dy

[/tex]

[tex]

1/A= \sqrt{\pi/2}

[/tex] From integral tables

That's the solution i came up with for the first normalisation

Is the second the same?

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