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Normalization Question

  1. Nov 11, 2004 #1
    How do I find the value of the normalization constant A for the wave function
    Ψ = Axe ^ (-x squared/2)? I know that I set it equal to 1, but do i do the integral from negative infinity to positive infinity; for no other limits are given?
     
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  3. Nov 11, 2004 #2

    Gokul43201

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    Sounds like this very same question has been asked before...that time with the square of the W.f'n. being the given qty...

    Yes, if unspecified, integrate from negative to positive infinity.
     
  4. Nov 11, 2004 #3
    So do I just end up with: ((-x squared)/2)Axe ^(-x squared/2), evaluated from negative infinity to infinity?
     
  5. Nov 12, 2004 #4

    Gokul43201

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    No, you want to find A from
    [tex]\int_{-\infty}^{\infty} \psi ^* (x) \psi (x) dx = 1 [/tex]

    [tex]=> \frac{1}{|A|^2} = \int_{-\infty}^{\infty} x ^2 e^{-x^2} dx [/tex]
     
    Last edited: Nov 12, 2004
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