# Normalizing a Wavefunction

1. May 15, 2015

### squelch

1. The problem statement, all variables and given/known data
A particle is described by the wavefunction:
$$\psi (x) = \{ \begin{array}{*{20}{c}} {A\cos (\frac{{2\pi x}}{L}){\quad\rm{for }} - \frac{L}{4} \le x \le \frac{L}{4}}\\ {0{\quad\rm{otherwise }}} \end{array}$$

(a) Determine the normalization constant A
(b) What is the probability that the particle will be found between x=0 and x=L/8 if a measurement is made?

2. Relevant equations

N/A

3. The attempt at a solution

Okay, just verify my logic for me:

(a) We integrate the wave function from -L/4→L/4, where the particle has a 100% chance of appearing, and set this integral equal to 1 (for the probability just mentioned):

$$1 = \int\limits_{ - \frac{L}{4}}^{\frac{L}{4}} \psi {(x)^*}\psi (x)dx$$

Integrating this (using Mathematica) and solving for A seems to point at $A = \pm \frac{2}{{\sqrt L }}$.

I'll only assume the positive value is valid since I'm not sure we can have a negative probability.

(b) Assuming that the normalization constant in part (a) is correct, we use our new normalization constant in our wavefunction and perform the same integration, this time over 0→L/8. Performing this operation seems to yield 40.9% (0.409).

2. May 15, 2015

### sk1105

Yes your logic is correct. You're right that we can't have a negative probability, but since the probability comes from $\psi ^*\psi$, the normalisation constant only ever appears as $A^2$, so it doesn't matter whether you pick the positive or negative value. Generally we pick the positive one just because positive numbers are easier to think about.