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Not clear on what happened (subtraction of two fractions with variables to exponents)

  • Thread starter Tubefox
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  • #1
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-2((1/((x^2 + 1)^2 )) - ((4x^2 )/(x^2 +1)^3 )) = 6x^2-2/(x^2+1)


This is actually the last step of this problem. I understand everything they did up until here, but I'm a bit confused as to how they got from their last step, to the actual answer. Could someone explain?
 

Answers and Replies

  • #2
CAF123
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Are you missing a '-' in front of the coefficient of the [itex] x^2 [/itex] term and should that be [itex] (x^2+1)^3 ? [/itex]
 
  • #3
Ray Vickson
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-2((1/((x^2 + 1)^2 )) - ((4x^2 )/(x^2 +1)^3 )) = 6x^2-2/(x^2+1)


This is actually the last step of this problem. I understand everything they did up until here, but I'm a bit confused as to how they got from their last step, to the actual answer. Could someone explain?
Don't you mean (6x^2 - 2)/(x^2 + 1)? You wrote 6x^2 - 2/(x^2+1), which is a completely different thing.

RGV
 

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