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Not so obvious 4th order DE

  1. Mar 25, 2007 #1
    1. The problem statement, all variables and given/known data
    solve the given differential equation:

    xy^(4) + 6y'" = 0

    2. Relevant equations

    No idea, I need something to get me started

    3. The attempt at a solution

    auxiliary equation:

    m^4 + 6m^3 = 0

    m^3(m+6)=0
    3 roots with m = 0 and the other root is m = -6

    so I got y = C1 + C2lnx + C3(lnx)^2 + C4x^-6

    but, it is not the solution. Your help is greatly appreciated. Thank You.
     
  2. jcsd
  3. Mar 26, 2007 #2

    cristo

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    I don't quite know what you're doing here. The method you are using here seems to be the one that you use for a second order equation, however this is an equation of 4th order.

    Take a look at the equation and try and spot a solution. In particular, you have a fourth derivative multiplied by x, and a third order derivative. Now, you know a function whose fourth derivative multiplied by x is equal to its third derivative (modulo constants). The function is xn. So, try the general solution y=xn. Plugging this into the ODE will give you a condition on n, which will enable you to obtain the particular solution.
     
  4. Mar 26, 2007 #3

    HallsofIvy

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    Your auxiliary equation is wrong. You appear to have used the auxiliary equation for a "constant coefficients" equation when you have a variable coefficient- and then used the "Euler type" solution.

    One way to handle this is to multiply then entire equation by x3 so that you get x4y(iv)+ 6x3y'''= 0, an "Euler-type" or "equipotential" equation. If you let y= xr you will get the correct auxilliary equation for this d.e.

    Much simpler is to let u= y'''. Now the equation is xu'+ 6u= 0, a simple, separable first order differential equation. After you have solved that, let y'''= u= your solution and integrate three more times.
     
  5. Mar 26, 2007 #4
    so the auxiliary method only works for 2nd order? Can you guys give me little more insight or any websites that would explain it to me further because my books was very vague in explain my problem or there were no example of such problem in the book. I hate my textbook. Thank you for your insights guys :shy:
     
  6. Mar 26, 2007 #5
    can you give me hint on how to solve an equation that involves a particular solution? Thank you:biggrin:
     
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