solve the given differential equation:
xy^(4) + 6y'" = 0
No idea, I need something to get me started
The Attempt at a Solution
m^4 + 6m^3 = 0
3 roots with m = 0 and the other root is m = -6
so I got y = C1 + C2lnx + C3(lnx)^2 + C4x^-6
but, it is not the solution. Your help is greatly appreciated. Thank You.