- #1

- 186

- 1

I don't see how this follows from Gauss's law.

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- Thread starter tronter
- Start date

- #1

- 186

- 1

I don't see how this follows from Gauss's law.

- #2

- 458

- 0

[tex]\frac{\frac{4}{3}\pi r^3}{\frac{4}{3}\pi R^3}=\frac{Q'}{Q}[/tex]

Thus: [tex]Q' = Q\frac{r^3}{R^3}[/tex]

Now use Gauss's Law to find the electric field inside the inner sphere.

- #3

- 85

- 0

Just to clarify what Snazzy said, the inner sphere is your Gaussian Surface.

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