- #1

- 8

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^{T}[C] to index notation.

I initially thought it would be D

_{ij}=A

_{ij}B

_{kj}C

_{kl}but I have doubts that this is correct.

Would anyone be able to elaborate on this?

Regards

- #1

- 8

- 0

I initially thought it would be D

Would anyone be able to elaborate on this?

Regards

- #2

Khashishi

Science Advisor

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Where did B come from?

- #3

- 8

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BWhere did B come from?

- #4

Khashishi

Science Advisor

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Err, did you edit your post? I didn't see a B in your equation before. Anyways, nevermind.

- #5

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No I never editted the equation. Do you have any ideas?Err, did you edit your post? I didn't see a B in your equation before. Anyways, nevermind.

- #6

Mark44

Mentor

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The OP had [B], which browsers treat as the start tag for bold fonts. That screwed up the equation. I edited the equation to fix that problem.Err, did you edit your post? I didn't see a B in your equation before. Anyways, nevermind.

- #7

Svein

Science Advisor

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OK. Let us start at the right. First: [itex]B^{T}_{j,k}=B_{k,j} [/itex], so [itex] (B^{T}\circ C)_{j,l}=\sum _{k}B^{T}_{j,k}C_{k,l}[/itex]. Then inset A at the front in the same way: [itex]A\circ (B^{T}\circ C)_{i,l}=\sum _{j}A_{i,j}(\sum _{k}B^{T}_{j,k}C_{k,l}) [/itex].I am having trouble converting [D]=[A][ B]T[C] to index notation.

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