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Note help / solution(s)

  1. Nov 29, 2012 #1
    1. The problem statement, all variables and given/known data
    Example: A person jumped off of a cliff into the water at a 26 degree angle. He traveled 23 meters (horizontally) and fell 12 meters (vertically). What was the person's velocity?


    2. Relevant equations
    X=Vxt + t
    Y=Vyt + 1/2at^2



    3. The attempt at a solution
    I was stuck instantly and I was sick the day we took these notes. So I don't know how to do these types of problems. (unless they're the 45 degree one)
     
  2. jcsd
  3. Nov 29, 2012 #2
    How is this so much different than a 45 degree problem? The only difference is the angle, wouldn't you just be able to do it like a 45 degree problem but use 26 degrees instead of 45?
     
  4. Nov 29, 2012 #3

    berkeman

    User Avatar

    Staff: Mentor

    Please see my posts in this similar thread about trajectory problems. They should help you understand the techniques used for these types of problems:

    https://www.physicsforums.com/showthread.php?t=655518

    .
     
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